Find the simple interest on ₹15,000 at 6% per annum for 4 years.
Correct answer: D. ₹3,600
SI = P × R × T ÷ 100 = 15,000 × 6 × 4 ÷ 100 = ₹3,600.
Solved quantitative aptitude MCQs on simple interest, compound interest, CI–SI difference, half-yearly compounding, growth and depreciation, with formulas and working.
These MCQs cover simple interest, the compound interest formula, compounding half-yearly, finding the rate or principal from an amount, and population growth and depreciation, which use the same formula.
Decide first whether the question is about simple or compound interest. For two years, the difference between CI and SI is P × (R/100)², a shortcut the explanations use.
Correct answer: D. ₹3,600
SI = P × R × T ÷ 100 = 15,000 × 6 × 4 ÷ 100 = ₹3,600.
Correct answer: D. 6%
Interest = 9,920 − 8,000 = ₹1,920. Rate = 1,920 × 100 ÷ (8,000 × 4) = 6%.
Correct answer: C. 10%
To triple, the interest must equal 2 × the principal, i.e. 200% in 20 years, so the rate is 200 ÷ 20 = 10% per annum.
Correct answer: C. ₹5,000
P = SI × 100 ÷ (R × T) = 1,200 × 100 ÷ 24 = ₹5,000.
Correct answer: A. ₹6,000
Interest for the extra 2 years = 8,400 − 7,200 = ₹1,200, i.e. ₹600 a year. Interest for 2 years = ₹1,200, so the sum = 7,200 − 1,200 = ₹6,000.
Read detailsCorrect answer: C. ₹1,655
Amount = 5,000 × 1.1 × 1.1 × 1.1 = ₹6,655, so CI = ₹1,655. Compare: simple interest would be only ₹1,500.
Correct answer: D. ₹22,050
Amount = 20,000 × 1.05 × 1.05 = 20,000 × 1.1025 = ₹22,050.
Correct answer: C. ₹36
For 2 years, CI − SI = P × (R/100)² = 10,000 × 0.06 × 0.06 = ₹36.
Correct answer: A. ₹1,640
Half-yearly means 5% for each of 2 periods: 16,000 × 1.05 × 1.05 = ₹17,640, so CI = ₹1,640.
Correct answer: B. 15 years
At compound interest the sum doubles every 5 years: 2 times after 5, 4 times after 10, 8 times after 15 years.
Correct answer: C. 8%
7,290 ÷ 6,250 = 1.1664 = (1.08)², so the rate is 8% per annum.
Correct answer: C. ₹31
CI = 1,331 − 1,000 = ₹331 and SI = ₹300, so the difference is ₹31.
Correct answer: D. 54,080
Population = 50,000 × 1.04 × 1.04 = 54,080 (growth works like compound interest).
Correct answer: C. ₹81,000
Value = 1,00,000 × 0.9 × 0.9 = ₹81,000. Depreciation is applied to the reduced value each year.
Correct answer: D. ₹540
Time = 6 months = 1/2 year. SI = 12,000 × 9 × 1/2 ÷ 100 = ₹540.
Correct answer: A. 10%
Interest = 7/5 − 1 = 2/5 of the sum = 40% in 4 years, so the rate is 40 ÷ 4 = 10% per annum.
Correct answer: B. ₹410
Amount = 4,000 × 1.1025 = ₹4,410, so CI = ₹410.
Correct answer: C. ₹6,000
The difference in rate is 2%, so 360 = P × 2 × 3 ÷ 100, giving P = ₹6,000.
Correct answer: B. ₹4,000
SI = 2,500 × 12 × 5 ÷ 100 = ₹1,500, so the amount is ₹4,000.
Correct answer: B. 10.25%
Each half-year earns 5%: 1.05 × 1.05 = 1.1025, so the effective annual rate is 10.25%.