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Mensuration Formula Sheet: 2D and 3D Shapes for SSC and Banking

All the area, perimeter, surface area and volume formulas you need for exams, with a worked example for each shape and the common traps.

By the World MCQ Forum India Editorial Team · 27 October 2026 · 3 min read

Mensuration questions are almost always direct: pick the right formula, put in the numbers, calculate. This page lists every formula you need, in the order exams usually test them. Unless a question says otherwise, take π = 22/7 and choose radii that are multiples of 7 to make the arithmetic easy.

Plane figures (2D)

Shape Perimeter Area
Rectangle (l, b) 2(l + b) l × b
Square (side a) 4a a², or (diagonal)² ÷ 2
Triangle (base b, height h) sum of sides ½ × b × h
Triangle (sides a, b, c) a + b + c √[s(s − a)(s − b)(s − c)], where s = (a + b + c) ÷ 2
Equilateral triangle (side a) 3a (√3 ÷ 4) × a²
Rhombus (diagonals d₁, d₂) 4 × side ½ × d₁ × d₂
Trapezium (parallel sides a, b; height h) sum of sides ½ × (a + b) × h
Circle (radius r) 2πr πr²
Semicircle (radius r) πr + 2r ½πr²

Worked example (Heron’s formula): sides 13, 14 and 15 cm. s = 21, so the area is √(21 × 8 × 7 × 6) = √7056 = 84 cm².

Rhombus side: its diagonals cut each other at right angles, so side = √[(d₁/2)² + (d₂/2)²]. With diagonals 12 and 16: √(36 + 64) = 10 cm.

Solid figures (3D)

Solid Curved / lateral surface Total surface area Volume
Cuboid (l, b, h) 2h(l + b) (four walls) 2(lb + bh + hl) l × b × h
Cube (side a) 4a² 6a² a³
Cylinder (r, h) 2πrh 2πr(r + h) πr²h
Cone (r, h, slant l) πrl πr(r + l) ⅓πr²h
Sphere (r) — 4πr² ⁴⁄₃πr³
Hemisphere (r) 2πr² 3πr² ⅔πr³

Useful extras:

  • Diagonal of a cube = a√3; diagonal of a face = a√2.
  • Diagonal of a cuboid = √(l² + b² + h²).
  • Slant height of a cone l = √(r² + h²).
  • A cone holds exactly one-third of a cylinder with the same base and height.

Scaling: what happens when dimensions change

Change Effect on area Effect on volume
Every length doubled × 4 × 8
Every length tripled × 9 × 27
Every length up 20% up 44% (1.2² = 1.44) up 72.8% (1.2³ = 1.728)

Wheel and distance questions

Distance covered in one revolution = circumference = 2πr.

Example: a wheel of radius 35 cm has a circumference of 2 × 22/7 × 35 = 220 cm. To cover 2.2 km (2,20,000 cm) it makes 2,20,000 ÷ 220 = 1,000 revolutions.

Common traps

  • Units: convert everything to the same unit before calculating. 1 m = 100 cm, but 1 m² = 10,000 cm² and 1 m³ = 10,00,000 cm³. Also, 1 litre = 1,000 cm³.
  • Hemisphere total surface includes the flat circle: 3πr², not 2πr².
  • Four walls of a room use 2h(l + b); the floor and ceiling are not included.
  • Semicircle perimeter includes the diameter: πr + 2r, not just πr.

Practise every formula in our mensuration set. All its answers were calculated by script.

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